VSEPR theory

The shape of water molecule is 

The bond angle in water molecule according to VSEPR theory is:

The bond angle in water molecule is $107°48\text{'}$.

Three bond pairs and one lone pair is present in water molecule.

The bond angle in ammonia molecule according to VSEPR theory is:

Ammonia has a tetrahedral structure with four electron pairs in the valence shell.

There are two bond pairs and two lone pairs present in ammonia molecule.

There are three bond pairs and one lone pair in the methane molecule.

In methane molecule, the expected bond angle is $107°48\text{'}$.

For methane molecule, the expected bond angle is,

What will be the geometry of ${\mathrm{BeCl}}_2$ molecule according to VSEPR theory.

The geometry of ${\mathrm{BeCl}}_2$ is:

The bond angle in ${\mathrm{BeCl}}_2$ is $120°$.

One lone pair of electron is present in ${\mathrm{BF}}_3$ molecule.

The geometry of ${\mathrm{BF}}_3$ molecule is:

The bond angle in ${\mathrm{BF}}_3$ molecule is:

The shape of ${\mathrm{BF}}_3$ is triagonal pyramidal.

Lone pairs occupy more space around the central atom than bond pairs.

Explain why the bond angle in water is $104°{31}^1$ instead of $109°{28}^1$?

Among the following which is known as electron-deficient molecule.